EllipseMathematics

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Question 1
EasyJEE

Theeccentricityeoftheellipsex2/a2+y2/b2=1(wherea>b)isgivenby:The eccentricity e of the ellipse x²/a² + y²/b² = 1 (where a > b) is given by:

A. e=1b2/a2e = \sqrt{1 - b²/a²}
B. e=1+b2/a2e = \sqrt{1 + b²/a²}
C. e=a2/b21e = \sqrt{a²/b² - 1}
D. e=1a2/b2e = \sqrt{1 - a²/b²}
Question 2
EasyJEE

The length of the latus rectum of theellipsex2/a2+y2/b2=1(wherea>b)the ellipse x²/a² + y²/b² = 1 (where a > b) is:

A. 2b2/a2b²/a
B. 2a2/b2a²/b
C. b2/ab²/a
D. a2/ba²/b
Question 3
EasyJEE

The coordinates of the foci of the standard ellipse x²/a² + y²/b² = 1 (a > b) are:

A. (±ae, 0)
B. (0, ±be)
C. (±a/e,0)(±a/e, 0)
D. (0,±b/e)(0, ±b/e)

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